ajax json 리턴하기, ModelAndView("jsonView")

1. pom.xml

<!-- JSON 라이브러리 -->
<dependency>
    <groupId>net.sf.json-lib</groupId>
    <artifactId>json-lib</artifactId>
    <version>2.3</version>
    <classifier>jdk15</classifier>
</dependency>
<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.5.1</version>
</dependency>

 

2.dispatcher-servlet.xml

<bean id="beanNameResolver" class="org.springframework.web.servlet.view.BeanNameViewResolver" p:order="0" />
<bean id="jsonView" class="org.springframework.web.servlet.view.json.MappingJackson2JsonView">
    <property name="contentType" value="application/json;charset=UTF-8"></property>
</bean>

bean 등록 한다.여기서 bean id "jsonView" 는 컨트롤러에서 사용되어진다.

 

3. Controller

@RequestMapping(value = "/menu/menuIdCheck.do", method = RequestMethod.POST)
public ModelAndView menuIdCheck(@RequestParam(required = false) Map paramMap){
    ModelAndView mv = new ModelAndView("jsonView");
    mv.addObject("result",menuService.selectMenuIdCnt(paramMap));
    return mv;
}